A. Eddy current loss
B. Hysteresis loss
C. Copper loss
D. Iron loss
Answer: C
Explanation:
B. Hysteresis loss
C. Copper loss
D. Iron loss
Answer: C
Explanation:
Short circuit test:
It is used to determine
- Copper losses in a transformer at full load
- Series branch parameters in ohmic values
- % resistance, % reactance and % impedance of the transformer
- We need to increase the applied voltage towards rated voltage up to rated current passes through the short-circuited secondary winding. It is conducted on the HV side of the transformer
- Since the applied voltage is small, the flux is also small. Therefore, core losses are small hence core loss can be neglected. Therefore, the wattmeter reading can be taken as equal to copper losses in the transformer.
- So, input power supplied during a short-circuit test on a transformer equals to copper losses.
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