MCQ-1 A 240V bulb passes a current of 4A. Calculate the power in the lamp.
(A) 950 W
(B) 960 W
(C) 930 W
(D) 850 W
Ans: (B) 960 W
Explanation:
Here Voltage V = 240 V
Current I = 4 A
Power P = ?
Power P = Voltage V * Current I
= 240 V * 4 A
= 960 W
The power in a lamp is 960 W.
MCQ-2 A current of 8A flows in a resistor of 4 ohms. Calculate the energy dissipated in 600 seconds in the resistor.
(A) 155.7 Killo Joule
(B) 156.3 Killo Joule
(C) 153.6 Killo Joule
(D) 152.5 Killo Joule
Ans:(C) 153.6 Killo Joule
(A) 950 W
(B) 960 W
(C) 930 W
(D) 850 W
Ans: (B) 960 W
Explanation:
Here Voltage V = 240 V
Current I = 4 A
Power P = ?
Power P = Voltage V * Current I
= 240 V * 4 A
= 960 W
The power in a lamp is 960 W.
MCQ-2 A current of 8A flows in a resistor of 4 ohms. Calculate the energy dissipated in 600 seconds in the resistor.
(A) 155.7 Killo Joule
(B) 156.3 Killo Joule
(C) 153.6 Killo Joule
(D) 152.5 Killo Joule
Ans:(C) 153.6 Killo Joule
Explanation:
Here Current I = 8 A
Resistance R = 4 ohm
Time T = 600 seconds
Energy E = ?
Power P = I2R
= 8 * 8 * 4
= 256 W
So power is 256 W
Now Energy E = Power P * Time T
= 256 * 600
= 153600 Joule
= 153.6 Kilo Joule
Hence the power dissipated in resistor is 153.6 Kilo Joule
